4p^2-16p-26=-8

Solution for 4p^2-16p-26=-8 equation:

4p^2-16p-26=-8

We move all terms to the left:

4p^2-16p-26-(-8)=0

We add all the numbers together, and all the variables

4p^2-16p-18=0

a = 4; b = -16; c = -18;
Δ = b2-4ac
Δ = -162-4·4·(-18)
Δ = 544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{544}=\sqrt{16*34}=\sqrt{16}*\sqrt{34}=4\sqrt{34}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{34}}{2*4}=\frac{16-4\sqrt{34}}{8}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{34}}{2*4}=\frac{16+4\sqrt{34}}{8}
$